If it's not what You are looking for type in the equation solver your own equation and let us solve it.
y^2-2.5y+1=0
a = 1; b = -2.5; c = +1;
Δ = b2-4ac
Δ = -2.52-4·1·1
Δ = 2.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.5)-\sqrt{2.25}}{2*1}=\frac{2.5-\sqrt{2.25}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.5)+\sqrt{2.25}}{2*1}=\frac{2.5+\sqrt{2.25}}{2} $
| 3y+10=y+52 | | p+5.6=11.2 | | 2x^2-6x=116 | | N-6=-n | | 15-10x=-5(1x+9) | | 8+6c=8c | | 4(x+1)^2=10 | | -5m=7-6m | | 2/9x-1/18=1/2 | | -66=6(x-8) | | 8x-4(4x)=-40 | | 2(3x-8)=4(x+5) | | 3n+130=8n-10 | | 1x-2=4-5x | | 3=12−3s | | -2(a+-24)=-28 | | -2/3x=-2/3x+8 | | 2(x^2+8)=16 | | 4(x+2)–2x=16 | | -x2-4x-2=0 | | x^2-2√(3x)+2=0 | | 16−4c=8 | | 6-9x=6x+9x-18 | | 20=4(f+1) | | c-428/16=19 | | -2.6(g-7)=0 | | 85=(-3+x) | | 24(j+5)=792 | | z8+ 49=57 | | -4x+6=46=x | | 21=24-3b | | 2(x+4)=0.5(4x-4) |